Indian Army Clerk Maths Online Test – Important Question

Indian Army Clerk Maths Online Test – Important Question(Army Clerk Exam Ki Taiyari): The most important section in the clerk written exam in which most of the candidates struggle a lot is Maths. Since the syllabus is vast there is a lot to study. The maths section carries 10 questions out of 25 that are asked in the first part. All those candidates who are preparing for the clerk post should know that it is important to practice maths daily along with the previous year paper and sample paper. With regular practice and hard work, you can achieve anything.

See also- Indian Army Clerk Written Exam Syllabus, Pattern, Marking Scheme

Here we are with some important questions of maths for Indian army clerk with full the explanation that has been collected from previous year paper. Now, you can give this online test of Maths and prepare yourself for the written exam. All the questions that are mentioned below are selected from exam point of view.

Along with maths you can also practice for- Indian Army Clerk General Knowledge(GK) Online Test

Indian Army Clerk Maths Online Test – Important Question(क्लर्क एग्जाम की तैयारी)

Q 1.The product of two numbers is 216 and their HCF is 3, what is their LCM?

  1. 648
  2. 72
  3. 219
  4. 231
  5. Answer is: 72
  1. Answer With Explanation
  2. We have given, product of two numbers= 216. HCF of two numbers= 3. We know that, LCM×HCF = Product of two numbers
    LCM×3 = 216
    LCM = 216/3
    LCM = 72

Q 2.A man buys a toy for Rs.100 and sells it for Rs.150. Then his gain percent is

  1. 50%
  2. 60%
  3. 30%
  4. 40%
  5. Answer is: 50%
  1. Answer With Explanation
  2. Cost price of toy(CP) = Rs 100
    Selling price of toy(SP) = Rs 150
    Profit % = (SP-CP/CP)×100
    = (150-100/100)×100
    = 50%

Q 3.In how many years will Rs.7500 double at 8% simple interest?

  1. 12
  2. 8
  3. 12.5
  4. 10
  5. Answer is: 12.5
  1. Answer With Explanation
  2. Principal = Rs 7500
    Rate% = 8
    Let the total amount be = A (where A = P+I)
    Let in X years A = 2P
    Now, 2P-P = P×R×T/100
    P = P×R×X/100
    X = 100/R
    X = 100/8
    X = 12.5

Q 4.Express 63 km/h into m/s

  1. 16.5
  2. 17.5
  3. 18.5
  4. 19.5
  5. Answer is: 17.5 m/sec
  1. Answer With Explanation
  2. 1 Km = 100 m
    1 hr = 3600 sec
    Hence, 63 km/hr = (63×1000/3600)m/sec
    = 63×5/18
    = 17.5 m/sec

Q 5.A fruit seller had some apples.He sells 40% apples and still has 420 apples.How many apples he had originally?

  1. 600
  2. 650
  3. 700
  4. 750
  5. Answer is: 750
  1. Answer With Explanation
  2. Let the actual number of apples be = a
    Now, he sold 40% of apples and are left with 420.
    a-(40/100)×a = 420
    100a-40a/100 = 420
    60a = 42000
    a = 42000/60
    a= 700

Q 6.If 2994/14.5 = 172, then 29.94/1.45 =?

  1. 172
  2. 17.2
  3. 1.72
  4. 0.172
  5. Answer is: 17.2
  1. Answer With Explanation
  2. We have given that, 2994/14.5 = 172
    (2994/14.5 × 1/10) = 172/10
    (29.94/1.45) = 17.2

Q 7.The angle of elevation of a ladder leaning against a wall is〖60〗^0 and the foot of the ladder is 4.6m away from the wall. The length of the ladder is

  1. 4.6
  2. 9.2
  3. 10
  4. 11.2
  5. Answer is: 9.2
  1. Answer With Explanation
  2. Angle of elevation = 60°
    Distance between wall and foot off ladder = 4.6
    Let the length of ladder be = H
    cos 60° = 4.6/H
    1/2 = 4.6/H
    H = 4.6×2
    H = 9.2 m

Q 8.The average of 20 values is 18. If 3 is subtracted from each of the value, then the new average will be

  1. 21
  2. 15
  3. 16
  4. 17
  5. Answer is: 15
  1. Answer With Explanation
  2. Let the sum of 20 values be = a
    then, a/20 = 18
    a= 20×18
    a= 360
    Now, 3 is subtracted from each values. So, total values subtracted from the sum is = 20×3= 60
    Remaining value= 360-60 => 300
    New average = 300/20 => 15

Q 9.The length of a tunnel, which a train 90 m long, travelling at 48 km/h, can cross in 21 s is

  1. 180
  2. 280
  3. 190
  4. 290
  5. Answer is: 190m
  1. Answer With Explanation
  2. Length of train = 90 m
    Speed of train = 48 km/hr
    = 48×1000/3600
    = 240/18 m/sec
    Time taken by the train = 21 sec
    Let length of platform = A
    Length of platform+length of train = speed of train×time taken
    A+90 = (240/18)×21
    90+A = 280
    A = 190 m

Q 10.What percentage is 390 g of 1 kg 500 g?

  1. 26
  2. 20
  3. 22
  4. 25
  5. Answer is: 26
  1. Answer With Explanation
  2. 1 kg 500 g = 1000 g + 500 g => 1500 g
    (390/1500)×100
    390/15 = 26%

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